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Conversation Between IIMarckus and PlatniumPiano
Showing Visitor Messages 1 to 4 of 4
  1. PlatniumPiano
    December 23rd, 2008 10:37 PM
    PlatniumPiano
    Lol good job.

    It's a paradox

  2. IIMarckus
    December 23rd, 2008 10:12 PM
    IIMarckus
    I was talking about this step:
    A(A+B-X)=-B(A+B-X)
    __________________
    (A+B-X)

    Which I assume translates to A(A + B − X) ÷ (A + B − X) = −B(A + B − X) ÷ (A + B − X). A = −B is a valid result from this step in all cases but one: when A + B − X = 0, because division by zero is undefined. Since the second line (A + B = X) specifically states that it is zero, the proof is invalid.

    You can see a similar error in this proof.

  3. PlatniumPiano
    December 23rd, 2008 04:52 PM
    PlatniumPiano
    Lol. yes that was a typo- (A+B)(A+B).
    The fourth step i have A= -B. This is 0. Therefore, A+B= 0, if you add the B to the side with the A. Now there is nothing there (0), so A+B=0.

  4. IIMarckus
    December 23rd, 2008 06:59 AM
    IIMarckus
    The math in your signature is faulty…
    (A+B)A+B=X(A+B) should be (A+B)(A+B)=X(A+B), though this is probably just a typo.

    The real problem with the math is in the fourth step. A + B − X = 0, so what you actually have is
    A × 0 = B × 0

    Which is, of course, true. Then you try to divide by zero. However, 0 ÷ 0 ≠ 1! Division by zero is undefined.


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