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jasonresno jasonresno is offline

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Visitor Messages

Showing Visitor Messages 46 to 60 of 105
  1. Patchisou Yutohru
    June 29th, 2009 8:14 PM
    Patchisou Yutohru

    I'm doing absolutely awesome! What about you? :3

  2. Patchisou Yutohru
    June 29th, 2009 8:11 PM
    Patchisou Yutohru

    You're baaaack \o/

  3. wolf
    June 28th, 2009 10:39 PM
    wolf

    Thanks~ :D

    Wow, and to plus 2 hours. :|

    Nothing really happening, just working on school as always... Good, nothing bad happened currently, you (other than your job)?

  4. Patchisou Yutohru
    June 28th, 2009 2:54 PM
    Patchisou Yutohru

    Now that you're baaaaaaack~

  5. wolf
    June 20th, 2009 3:17 PM
    wolf

    Yay! \o/ Busy with life? X3

  6. Patchisou Yutohru
    June 20th, 2009 1:03 PM
    Patchisou Yutohru

    Took you forever.

  7. wolf
    May 4th, 2009 3:05 PM
    wolf

    You left. ._.

  8. Patchisou Yutohru
    April 10th, 2009 6:36 PM
    Patchisou Yutohru

    Boooo. Where are you? >:[

  9. Tiny
    February 22nd, 2009 6:21 PM
    Tiny

    lol what??

  10. .inLOVE
    February 10th, 2009 2:22 PM
    .inLOVE

    Aw, thank you! He didn't really have a name, and Satoshi was really handsome in my eyes, er, ears. xD

  11. .inLOVE
    February 10th, 2009 2:17 PM
    .inLOVE

    Hehehe, no problem. BTW, hi. xD

  12. .inLOVE
    February 10th, 2009 1:53 PM
    .inLOVE

    I dissected your dream ;D

  13. Patchisou Yutohru
    February 9th, 2009 3:07 PM
    Patchisou Yutohru

    It's fun to stalk your posts...

  14. Patchisou Yutohru
    February 6th, 2009 4:05 AM
    Patchisou Yutohru

    The kind that hurts my brain:

    Quote:
    PSH YOU GET IT ANYWAY

    First one is done by factoring. I'm not sure how they're teaching you but I just do it by eye.

    So you have
    x²+4x-12=0

    Since the highest power of x is two, you know you're looking for two roots: the values of x at zero. You have no coefficient in front of the x², so you know your answer is going to look something like this: (x + a)(x + b)=0 where a and b are either positive or negative numbers.

    When you're factoring like this, here's a trick: your two numbers will ALWAYS be factors of the number without an x. In this case, it's -12. So the factors of that are ±1, ±2, ±3, ±4, ±6, ±12. Those are the only numbers you can possibly have. So technically you could just start guessing combinations until you get it right but that might take forever. :P It does help to list them out though.

    So! When you use FOIL, the two numbers you're looking for become the +4 and -12 in your expanded equation. You get the +4 by adding two of the numbers together and the -12 by multiplying two of the numbers together. So you know you're looking for some a+b=4 and a×b=-12. The only combinations you have are (these are all ±) 1×12, 2×6 and 3×4. You know one of them has to be positive and one has to be negative. So what positive and negative numbers add up to give you 4? With a little thinking, the only answer can be a=-2 and b=6 which gives -2×6=-12 and -2+6=4.

    So tossing a and b back into your factored equation gives you (x-2)(x+6)=0. You can always just expand with FOIL again to check your work and make sure you did it right. :D

    It took me an hour to finish that (only, of course.. there were more than that). >:[

  15. Patchisou Yutohru
    February 5th, 2009 9:09 PM
    Patchisou Yutohru

    Homework, unfortunately. :|

    And here I was thinking I'd get my nine hours or so of sleep...

About Me

  • About jasonresno
    Biography
    I'm an actor, writer, and certifiable day dream. I love my friends, my family, and all that is fiction.
    Interests
    Acting, Writing/Literature, Sports, Anime, Cinema.
    Location
    Illinois
    Gender
    Male ♂
    Occupation
    Actor
    Nature
    Quiet
  • Signature


    “The simplest things are often the truest.”

    [Blog] - [Fiction] - [AMA]

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General Information
  • Last Activity: November 16th, 2015 9:14 AM
  • Join Date: January 29th, 2005
  • Referrals: 0

Friends

Showing Friends 1 to 11 of 11

Emblems

Emblem Showcase - 4 Total
  Emblem
Community supporter
These helpful members donate their money to help make PC a better place.
Awarded: January 1st, 2009 12:37 PM
PC Veteran
These old folks have been around for far too long but we love them anyway.
Awarded: January 2nd, 2009 3:58 PM
The PokéFilm Connoisseur
Thank you so much for coming to GT11's Pokémon Movie Night! Starring Bob, Cheerio, Marty, Einstein, Chip and Dip. We had a blast ~
Awarded: July 15th, 2015 10:48 AM
GT 12 Arcade Participant
Thank you for participating in GT 12's Arcade Event, we hope you had fun!
Awarded: July 15th, 2015 3:14 PM

Blog

Latest Blog Entry

Posted January 1st, 2009 at 12:55 PM by jasonresno Comments 4
Posted inUncategorized

Today, I made a Tier 5 donation to the Pokemon Community Forum and I couldn't be happier. It feels good to give to a forum and community that deserves it and I hope that I will be here for many years and that we all will be as well. I look forward to getting to know to all of you!

Recent Comments

Yay, welcome! It...

Posted January 1st, 2009 at 9:36 PM by Lucy Lu Lucy Lu is offline

Nice to add another...

Posted January 1st, 2009 at 4:53 PM by Gerri Shin Gerri Shin is offline

Awesome! Glad you've...

Posted January 1st, 2009 at 4:35 PM by Thomas Thomas is offline

Finally. ...

Posted January 1st, 2009 at 1:33 PM by

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