that guy [TCTI v 8]
View Single Post
February 11th, 2013 (8:32 AM).
Do the Toxic Waltz
If you can do simple math, tell me what is the integral of F·dr (dot product between the vectors F and dr), where F is the vectorial function whose coordinates are given by (10x^4 - 2x*y^3 ; -3x^2*y^2) and dr is the position differential vector of coordinates (dx; dy) along the path given by x^4 - 6x*y^3=4y^2, from the starting point (0;0) to the final point (2;1).
It's quite simple actually.
The curl of the function F is zero (d/dy (10x^4 - 2x*y^3) = -6x*y^2 = d/dx (-3x^2*y^2)), and as such the path you integrate the function along doesn't matter. Find the scalar function G whose derivative with respect to x is the first coordinate of F and whose derivative with respect to y is the second coordinate of F ---> G=2x^5 - x^2*y^3. Just do G(2;1)-G(0,0) and done! The final result is 60.
Blaarh, I tried to translate the names of that stuff as best as I could.
Also, I should do the same as Went.
"The perfect plan must have an alibi,
and the perfect pawn to spew the party lines
of the perfect falsehood spoke a thousand times...
The perfect words cover the greatest crime"
Joined Oct 2006
Also Known As:
Gabriel / Gabri
View Public Profile
Send a private message to Katalyst
Find all posts by Katalyst
Find threads started by Katalyst
Ignore Posts by Katalyst