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-   -   4th Gen pokemon full party challenge (https://www.pokecommunity.com/showthread.php?t=164573)

EverPhoenix December 29th, 2008 4:33 PM

pokemon full party challenge
 
heres an interesting (maybe easy, i dont know) challenge i thought of. i consider it a challenge as such because it is almost the complete opposite of my style of play.

basically, what you have to do:

1. ASAP, get all 6 pokemon you want to raise in the challenge (no legendaries allowed).
2. You must evenly raise them all (they must all be within 1 or 2 levels of each other at all times)

basically thats the main idea. any further optional rules you may choose:
-no imported pokemon (egg moves, iv breeds , imported TMs)
-no extra leveling (keeping vs seeker use to a minimum and not spending absurd amounts of time crawling through grass)

if anyone thinks of any more, feel free to post and ill make the additions.

the reason i consider this to be any form of a challenge is that most people i know who play only raise 3 at a time. by evenly raising all 6, you should be of lower level than if you were raising less. this should make the game slightly more challenging.

Feign December 29th, 2008 6:40 PM

Lol, I already evenly raise mine, generally, when I battle against AIs, I am +/- 3 levels to them. I've also noticed that I level faster in Diamond than I have in the past with Blue/Red. By doing so, it gives me more choice on what I should fight against my opponent, especially if I can take advantage of them.

EverPhoenix December 29th, 2008 7:02 PM

Quote:

Originally Posted by Feign (Post 4235422)
Lol, I already evenly raise mine, generally, when I battle against AIs, I am +/- 3 levels to them. I've also noticed that I level faster in Diamond than I have in the past with Blue/Red. By doing so, it gives me more choice on what I should fight against my opponent, especially if I can take advantage of them.

looks like this isnt much of a challenge then. i played it through using 3 pokemon and i found i was about the same level (starter was always 5-10 higher than everyone else)


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