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I just had a thought
In some areas where you have to fight wild 2-on-2 battles, if you want to catch one of the pokemon you have to defeat the other one first. So, what if both of the pokemon were shiny. How would you react to that?
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Most of the time when I fight double wild battles they are the same Pokémon, so if I got two shinies in one battle (though I doubt I ever will) I would just finish off the other Pokémon and catch the last shiny.
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Well, if they were different pokemon, I would find out which was a more common pokemon and which was the rarer pokemon. I'd obviously go for the rarer one.
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I'd just go for the one that I like better... or has the better colouring effect. It kinda does suck that you can't catch more than one in a double battle.
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but i bet u anything the person you're battling with would faint the pokemon
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The chance of finding a shiny is around 0.01%. The chance of finding two shinies in the same battle is half of that. A million zeny to whomever legally makes that encounter. :P
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Wait a sec.. shouldn't it be smaller than half the normal chance? As the chances of one is 1/8192 and probablity-wise you multiply to get the outcome. => 1/8192 * 1/8192 = 1/67 108 864 Anyway... it's a small and very unlikely chance... xD |
Yup, that's the right math.
This is thread shouldn't be here IMO. Its pointless because it's probably never going to happen, and besides, what do you think you should do. Would you go for the Shiny Starly over the Shiny Scyther? Try using a little common sense. |
As annoying as it would be I'd just finish one off and catch last 1
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i would probably go crazy choosing which one unless it was like a bidoof and a rare pokemon
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or in some derranged hack version of pokemon, you fight lugia and ho-oh at the same time: they somehow both managed to be shiny. choose wisely
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