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Need Some PHP Help

Tyler

PHP Scripter
    • 620
    Posts
    20
    Years
    Im always getting a "Could not execute error" and i dont know what im doing wrong can someone please help me. I have all my database info set up it just doesnt want to execute

    Form Script:
    HTML: 
    <html>
<head>
</head>

<body>
<form action="register2.php" method="post">
Username: <form type="text" name="user" value="user"><br>
Password: <form type="password" name="pass" value="pass"><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
    PHP Script:
    PHP: 
    <html>
<head>
</head>
<body>
<?php 
    $self = $_SERVER['PHP_SELF'];
    $user = $_POST['user'];
    $pass = $_POST['pass'];


{ $conn = @mysql_connect( "localhost", "u70423688","284ad1" )
    or die("Could not connect to MYSQL"); #Connecting to MYSQL
$db = @mysql_select_db( "d60385531", $conn )
    or die("Could not select database"); #select database
$sql = "insert into users
    (user,pass) values
    (\"$user\",password(\"$pass\") )";
$result = @mysql_query( $sql, $conn )
    or die("Could not execute query");
if( $result ) { echo( "New user $user added" ); }
}
?>
</body>
</html>
     
    Ausaudriel said:
    You just messed up your form.
    Click to expand...

    It wouldn't be the HTML, cause the PHP is generating that error. It's obviously a problem with your SQL statment, which is the following piece of code:

    $sql = "insert into users
    (user,pass) values
    (\"$user\",password(\"$pass\") )";
    $result = @mysql_query( $sql, $conn )
    or die("Could not execute query");
    Click to expand...

    Personally, I would change it to something like this:

    PHP: 
    $result = mysql_query("INSERT INTO users (user, password) VALUES ('$user', '$pass')") or die("Could not execute query!");

    And I would md5 the password in PHP, cause I don't know what the password function that you have included in your query does.

    Hope that helps!
     
    But I'm looking at both his and yours side by side, and there's no difference. How could the form be the problem?

    And I would suggest adding mysql_error() to your die so you can see the actual reason for the error.
     
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