[Other] How many flags in a byte?

Using a routine that needs a certain amount of flags. How many flags are in a single byte of RAM? I thought it was 8 but a simple test setting flags doesn't show that. Here is the routine that needs it, for context.

Using save block hack with repointed flags, if that matters.

Thanks!

a flag is a word type. A word has 0000-ffff 65535. A flag can only accept one or zero. In one byte, 00-ff means one flag in two bytes

There are indeed eight flags in a byte. Each flag sets a different bit in the byte. So if you set the eighth flag in the byte, the byte will then add 0x80 to whatever value was there before. For example, if you have flags 0x900 - 0x907 in a single byte, setting flags 0x900, 0x902, 0x903, and 0x907 will set the byte to 0x1 + 0x2 + 0x4 + 0x80 = 0x87. Does that make sense?

Dinisk said:

a flag is a word type. A word has 0000-ffff 65535. A flag can only accept one or zero. In one byte, 00-ff means one flag in two bytes

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You're referring to a var, not a flag. Flags are bit set, meaning their values can only be 0 or 1.