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I don't see how jumping over a plane would break the laws of physics. I mean, if you can exert a high enough force to reach the speed required to go over the height at which the plane is, then it would be possible.
If you weighed about 70 kg and the height of a plane is 12000 m, at the top of the arc, you'd have a Velocity of 0, so:
m = 70 kg
y = 12000
Vf = 0 m/s
Also, law of conservation of mechanical energy states that:
KEi + PEgi + PEei = KEf + PEgf + PEef
Since we only have Kinetic energy in the beginning and potential gravitational energy at
the end, it would be:
KEi = PEgf
KE (Kinetic Energy) is equal to 1 half the mass times velocity squared and Potential Gravitational energy is equal to mass times gravity times height, so that would be:
(1/2)mV^2 = mgh
Cancel the weights and we get:
(1/2)V^2 = mgh
Solve for velocity and we get:
V = √ (2mgh)
Now plug in the values (g = gravity and is a constant force of 9.81 m/s):
V = √ (2(70)(9.81)(12000)
Simplify and we get:
V = 1283 m/s
Since Change in Kinetic Energy is equal to Work and Work is Force times distance, we get:
(1/2)mV^2 = Fd
Solve for force and we get:
F = (1/2)mV^2 / d
Plug in the values and we get:
F = (1/2)(70)(1283^2) / 12000
Simplify and we find out that in order to jump over a plane, the average person needs to exert:
F = 4801 N
Just find a way to exert a force of nearly 5000 Newtons and you're good. :x