Fizzbuzz

[twocows]

All you would-be programmers out there, here's a fairly simple program that you should be able to write in under 5 minutes, 10 tops. If you can't do it, you need to work on your problem solving A LOT. It's an extremely easy program that's often used to screen out people who don't know what they're doing when applying for jobs.

Output the numbers from 1 to 100, except replace multiples of 3 with "fizz," multiples of 5 with "buzz," and multiples of 3 AND 5 with "fizzbuzz."

I was able to think of a solution in two minutes and write the code in C in another two, and this was at 3:00 AM. Give it a try.

 

[NOOBLMAO]

easy...

#include <iostream>
using namespace std;
void main()
{
cout << "1\n2\nfizz\n4\nbuzz\nfizz\n7\n8\nfizz\nbuzz\n11\nfizz\n13\n14\nfizzbuzz\n16\n17\nfizz\n19\nbuzz\nfizz\n22\n23\nfizz\nbuzz\n26\nfizz\n28\n29\nfizzbuzz\n31\n32\nfizz\n34\nbuzz\nfizz\n37\n38\nfizz\nbuzz\n41\nfizz\n43\n44\nfizzbuzz\n46\n47\nfizz\n49\nbuzz\nfizz\n52\n53\nfizz\n55\n56\nfizz\n58\n59\nfizzbuzz\n61\n62\nfizz\n64\nbuzz\nfizz\n67\n68\nfizz\nbuzz\n71\nfizz\n73\n74\nfizzbuzz\n76\n77\nfizz\n79\nbuzz\nfizz\n82\n83\nfizz\nbuzz\n86\nfizz\n88\n89\nfizzbuzz\n91\n92\nfizz\n94\nbuzz\n96\n97\n98\nfizz\nbuzz";
}

 

[Captain Fabio]

easy...

#include <iostream>
using namespace std;
void main()
{
cout <<

Spoiler:

"1\n2\nfizz\n4\nbuzz\nfizz\n7\n8\nfizz\nbuzz\n11\nfizz\n13\n14\nfizzbuzz\n16\n17\nfizz\n19\nbuzz\nfizz\n22\n23\nfizz\nbuzz\n26\nfizz\n28\n29\nfizzbuzz\n31\n32\nfizz\n34\nbuzz\nfizz\n37\n38\nfizz\nbuzz\n41\nfizz\n43\n44\nfizzbuzz\n46\n47\nfizz\n49\nbuzz\nfizz\n52\n53\nfizz\n55\n56\nfizz\n58\n59\nfizzbuzz\n61\n62\nfizz\n64\nbuzz\nfizz\n67\n68\nfizz\nbuzz\n71\nfizz\n73\n74\nfizzbuzz\n76\n77\nfizz\n79\nbuzz\nfizz\n82\n83\nfizz\nbuzz\n86\nfizz\n88\n89\nfizzbuzz\n91\n92\nfizz\n94\nbuzz\n96\n97\n98\nfizz\nbuzz";

}

LOL at the hard-code! XD

That isn't really that hard too be honest. We have to do things like that in C++ every week for our hand-ins ><

 

[Dawn]

This seems like it would be incredibly easy to make in Python. Just output 1-100 with a simple if and else to check if it's a multiple of 3 or 5

 

[Hohoo]

23 lines in Vala.

public static int main (string[] args) {
    string re;
    
    for (int i = 1; i < 101; i++) {
        re = "";
        
        if (i % 3 == 0) {
            re += "fizz";
        }
        
        if (i % 5 == 0) {
            re += "buzz";
        }
        
        if (re != "") {
            stdout.printf ("%s\n", re);
        } else {
            stdout.printf ("%d\n", i);
        }
    }
    
    return 0;
}

 

[twocows]

Don't forget multiples of 3 and 5.

Here is my code. I didn't include it initally to give people a chance to try it out.

// |fizzbuzz.c|: Fizzbuzz

#include <stdio.h>

int main()
{
    for(int a = 1; a < 101; ++a)
    {
        if (a % 3 == 0 && a % 5 == 0)
            puts("Fizzbuzz");
        else if (a % 3 == 0)
            puts("Fizz");
        else if (a % 5 == 0)
            puts("Buzz");
        else
            printf("%i\n", a);
    }
}

And yeah, most of the stuff I do in my C assignments is much harder than this.

 

[Hohoo]

Don't forget multiples of 3 and 5.

I didn't. I made it this way:

• Start with an empty string
• If i is a multiple of 3, add "fizz"
• If i is a multiple of 5, add "buzz"

In other words: if i is a multiple of both numbers, the string will also have both "fizz" and "buzz" in it.

 

[twocows]

I didn't. I made it this way:

• Start with an empty string
• If i is a multiple of 3, add "fizz"
• If i is a multiple of 5, add "buzz"

In other words: if i is a multiple of both numbers, the string will also have both "fizz" and "buzz" in it.

Ah, I see, not bad. That's probably more efficient, actually.

 

[Deleted member 12729]

Gotta love being late to the party:

public class Lol {
    public static void main(String args[]) {
        for (int i = 1; i < 101; i++) {
            if (i % 3 == 0 && i % 5 == 0)
                System.out.println("Fizzbuzz");
            else if (i % 3 == 0)
                System.out.println("Fizz");
            else if (i % 5 == 0)
                System.out.println("Buzz");
            else System.out.println(i);
        }
    }
}

Anything else? :P

 

[Hohoo]

11-line Python version:

if __name__ == "__main__":
    for i in range(1, 101):
        s = ""
        if not i % 3:
            s += "fizz"
        if not i % 5:
            s += "buzz"
        if s is not "":
            print(s.capitalize())
        else:
            print(i)