~Autumn Daily Chit Chat~

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There are ignorant mods, and then there are just some who are just full of themselves b/c they are mods... ._. they treat normal members like they are just stupid newbs who dont read the rules...*snort*

Simon-mod *pokes w/ gaming controler >3*

POST 3000! >D
 
...I need help with my Chem AP homework...

A cylindrical bar of gold that is 1.5in. high and 0.25in. in diamter has a mass of 23.1984g, as is determined on an analytical balance. An empty graduated cylinder is weighed on a triple-beam balance and has a mass of 73.47g. After pouring a small amount of liquid into the graduated cylinder, the mass is 79.16g. When the gold cylinder is placed in the graduated cylinder (the liquid covers the top of the gold cylinder), the volume indicated on the graduated cylinder is 8.5mL.

Assume that the temperatures of the gold bar and the liquid are 86?F. If the density of the liquid decreases by 1.0% for each 10?C rise in temperature (over the range 0 to 50?C), determine

a. the density of the gold at 86?F.
b. the density of the liquid at 40?F.
Note: Parts (a) and (b) can be answered independently.
So...any chem majors here?
 
Simon said:
...I need help with my Chem AP homework...

So...any chem majors here?
Tabatha: Scanning....
.....
......
OVERLOAD *shutdown*

Aw heck, you broke my avatar...>> she's mad at u....

EDIT: I'm only in Biology...^^;;
 
Simon said:
...I need help with my Chem AP homework...

So...any chem majors here?
*Scans*

I would go with B. Why?...don't ask!
 
>.< All I've done is subtracted the weight of the graduated cylinder without the liquid from the weight of the graduated cylinder with the liquid, giving me 5.69g, the weight of the liquid. I think. From there, I have no idea what to do...

Come on...someone in this community has to know chemistry. And this is only chapter one...
 
Simon said:
>.< All I've done is subtracted the weight of the graduated cylinder without the liquid from the weight of the graduated cylinder with the liquid, giving me 5.69g, the weight of the liquid. I think. From there, I have no idea what to do...

Come on...someone in this community has to know chemistry. And this is only chapter one...
This is a pokemon forum. Half of the members dont even know Divison.

Try searching on Google.
 
I hope she does. She's been viewing the thread for a while...

EDIT: What on Earth makes you think Google has the answer?
 
*tweaks Tabatha* Yay! She's rebooting! :3

lol, google has everything....you just need to learn how to search it...in fifth grade I found all of the answers to my vocab book by doing a google search...

the website got banned though v_v
 
Chibi-chan said:
Wanna know something funny?
B is another question. Not an option XD

It seems like the Typhlozion has the answer though...
Opps. :shocked:

Kelesy is very smart. She should know the answer. Ashley may know too.
 
Simon said:
...I need help with my Chem AP homework...

So...any chem majors here?
I did something just like that last year...I think I might have the paper around here O_o
 
Mihara said:
I did something just like that last year...I think I might have the paper around here O_o
GIIIIMMMMMEEEE!!! I mean...could you tell me the answer plus show all the work?

This problem is worth 20 points alone and the chem teach claims that this will be an "average" problem by the second semester.
 
Mihara said:
I did something just like that last year...I think I might have the paper around here O_o
Bum bum! :o Someone might actually be smart and answer the question! :o

pfft, I could try, but you'd get these wierd crazy #'s XP
 
...yeah, AP will screw you over like that.

I think all you have to do is cut the density of the liquid in half and double it for the gold. Then you'd add 36 to every 10C until you get to 86 and 40 and then that's the density...I think. O_o *hasn't done AP chem in forever*
 
And...what would the density of the liquid be? 5.69g?

F= 1.8(10) + 32 = 50?F for every 10?C
86?F / 50?F = 1.72

I have no idea what I just did up there...

Where'd you get 36 from?
 
Omg stop with the school work @_@ *is going through some major anxiety attack*
 
Simon said:
And...what would the density of the liquid be? 5.69g?

F= 1.8(10) + 32 = 50?F for every 10?C
86?F / 50?F = 1.72

I have no idea what I just did up there...

Where'd you get 36 from?
From the conversion rate of C to F, one of my teachers last year said to add 36 whenever you do that.

f=1.8(10) + 32= 50?F for every 10?C
So assuming 5.69g is the density of the liquid...

86?F/ 50?F= 1.72 + 5.69g= 7.44 or 43.44g (?)

Hell I don't know, I haven't done this in forever O_o
 
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