Nihilego

Try this in the mean time:

xMsyOowMaEY

Well I just started my master's program now. Organic Chemistry in a multitude of courses, hard core and detailed with lots of focus on lab work. So much fun, gawd. It's more diverse than some think... I think xD

Certainly important with stereoisomers in drug production. That's my line of study ;)

Not a problem, it's fun when I know things for a change, haha. Let me know if there's anything else.

Just watched it again. Still holds up and is hilarious after countless rewatches.

Exactly, no. Because C1 has "two" O and C2 has two H.

Yes, that. "out" and "into" the plane, depending on how you draw it really. I always found it difficult to twist a molecule around to determine R or S when the H (or lightest group) wasn't already pointed back :(

Ooh, biochemistry -> amino acids. Now I get why you were talking L and D. Aren't all amino acids in the body either L or D? Can't remember which. But we only use one form. That has to do with how the molecule twists plane polarized light... unless I'm mixing things up in my head now.

Sorry :3

I only took C2 as an example to explain R and S. C1 isn't chiral. Only C2 and C3 are. And C2 is definitely something that C3 and C1 binds to, yes. It's a C, and in C3's case, it binds to several Cs, C2 being one of them. Then you have to consider what group weighs more - CH3 or a C bonded to N, H and C. (it's the latter, obv).

You know what fischer projection is?

Did I scare you or what lol

too busy with egc to remember to visit here as much as i should :c

i'm good! working on a full time job, getting ready to move out as well~

First rule: R and S should not be connected with L and D, even if it seems so :p something biological, light turning shizzle. If one atom is R, it could be D or L, it's not always connected.

Okay look at C2. It has H, N, C and C to bind to. Arrange those with the lightest as the highest number - H is 4 and N is 1. Since H's atomic weight is ~1 and N is 14.01, right? C is ~12. The two carbons, we have to look at what they bind to. A double bond counts as two identical atoms, so C1 "binds" to three oxygen, which has more weight than C3's O, C and H. So C1 is labeled 2 and C3 is labeled 3. Because C1 weighs more than C3 since it binds to heavier groups in turn.

Now, we have been told that C2 is S configuration, so that means that if we write that part of the molecule tetrahedrically, we should make number 4 (H) point "into the paper" and arrange the other atoms binding to C2 so that when you start at the atom labeled 1 and count to 2 and 3 (skipping 4!) you should notice that you are going anti-clockwise around C2. Anti-clockwise = left = sinister = S.

Likewise, if you have an atom where the chirality is already drawn but not named, you can simply twist it so that the lightest group bonded to it points into the paper, and then count to see if it's R or S.

Making any sense here?

I haven't heard it labeled like that either actually :p But my guess would be that it's carbon no 2 and no 3 (counting the carbonyl as 1 I presume) and S and R should denote the arrangement of the atoms around them yeah. Sinister and Rectus, you know how to do that?

Anytime~ Can't promise I'll be super much help but xD What's it about? Cells? Rates? Drugs?

okay.

also love for nathan's vm.

tiniest avatar.

it's okay unkempt harold

i am awesome

help me

help i am 12 what do i do